Jane Seymour (b. February 15, 1951) portrayed Genevieve Teague on the series Smallville.
- Pictured: Jane Seymour as Genevieve Teague from the Smallville episode "Pariah"
Work History
Acting Credits
Smallville | 2001-2011 | Genevieve Teague |
---|---|---|
"Bound" | November 17, 2004 | Genevieve Teague Duchess Gertrude |
"Pariah" | February 2, 2005 | Genevieve Teague |
"Krypto" | February 16, 2005 | Genevieve Teague |
"Ageless" | May 4, 2005 | Genevieve Teague |
"Forever" | May 11, 2005 | Genevieve Teague |
"Commencement" | May 18, 2005 | Genevieve Teague |